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NotesEENG 3345: AC Circuit Analysis Lecture 7

Frequency Response and Filters

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Table of Contents

Determining Frequency Response Experimentally

Gain, Phase Shift, and Transfer Function

$$H_(j\omega) = |H(j \omega)| \angle H(j \omega) = \frac{X_{\text{out}}(j \omega)}{X_{\text{in}}(j \omega)}$$

Bode Plot

bode plot example

Example 07.1.
07 Frequency Response and Filters 2025-07-08 10.47.47

MATLAB

1R = 1e4;
2L = 10e-3;
3C = 100e-6;
4w = logspace(0, 5, 40);
5temp = (w * L - 1 ./ (w*C));
6gain = w*L ./ sqrt(R**2 + temp .^ 2);
7phi = -atand(temp / R);
8figure(1), semilogx(w, gain), grid;
9figure(2), semilog(w, phi), grid;

RLC Filters

Drop-off Frequencies

Cutoff Frequencies

Generalized Second-Order Circuits with Complex Roots

$$ H(j \omega) = \frac{k}{1 - \left( \frac{\omega}{\omega_0} \right)^2 + j 2\zeta \left( \frac{\omega}{\omega_0} \right)} $$

where $\zeta = \frac{\alpha}{\omega_{0}}$

Three Subcases:

  1. Low-frequency regime: $\omega \ll \omega_0$
    • Magnitude: $|H| \approx k$
    • Phase: $\angle H \approx 0^\circ$
  2. At resonance: $\omega = \omega_0$
    • Magnitude: $|H| = \frac{k}{2\zeta}$
    • Phase: $\angle H = -90^\circ$
  3. High-frequency regime: $\omega \gg \omega_0$
    • Dominant term is $-\left( \frac{\omega}{\omega_0} \right)^2$ in the denominator
    • Magnitude: $|H| \approx \frac{k \omega_0^2}{\omega^2}$ (i.e., rolls off as $1/\omega^2$)
    • Phase: $\angle H \approx -180^\circ$

General Second-Order Transfer Function Decomposition

$$ H(j\omega) = \frac{k}{(1 + j \omega / p_1)(1 + j \omega / p_2)} $$ $$H(j \omega) = H_{1}(j \omega)H_{2}(j \omega)H_{3}(j \omega)$$

where

Log-Magnitude Decomposition

$$ \begin{align*} |H(j\omega)|_{dB} &= 20 \log_{10}(|H_1|) + 20 \log_{10}(|H_2|) + 20 \log_{10}(|H_3|) \\ &= 20 \log_{10}(k) - 20 \log_{10}\left(\sqrt{1 + \left(\frac{\omega}{p_1}\right)^2}\right) - 20 \log_{10}\left(\sqrt{1 + \left(\frac{\omega}{p_2}\right)^2}\right) \end{align*} $$

References

Sources

Graph