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NotesFundamentals of Electric Circuits (Sadiku) Lecture 2

Basic Laws

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Table of Contents

Resistance and Ohm’s Law

Resistance

Definition 02.1.

Resistance is the behavior of a material to resist the flow of electric charge, represented by

$$R = \rho \frac{\ell}{A},$$

where $\rho$ is the resistivity in $\Omega m$, $\ell$ is length, and $A$ is cross-sectional area.

Resistivities of Common Materials

Material Resistivity (Ω·m) Usage
Silver 1.64 × 10⁻⁸ Conductor
Copper 1.72 × 10⁻⁸ Conductor
Aluminum 2.8 × 10⁻⁸ Conductor
Gold 2.45 × 10⁻⁸ Conductor
Carbon 4 × 10⁻⁵ Semiconductor
Germanium 47 × 10⁻² Semiconductor
Silicon 6.4 × 10² Semiconductor
Paper 10¹⁰ Insulator
Mica 5 × 10¹¹ Insulator
Glass 10¹² Insulator
Teflon 3 × 10¹² Insulator

The Resistor

Types of Resistors

Ohm’s Law

Definition 02.2 (Ohm's Law).

The voltage $v$ across a resistor is directly proportional to the current $i$ through the resistor.

$$v \propto i$$

The proportionality constant for this relationship is the resistance, $R$. So, the equation becomes

$$v = iR.$$
Definition 02.3 (Short Circuit).

Any circuit element with $R \rightarrow 0$. In practice, this is a connecting wire between two points in the circuit, in which the charge carriers take the path of least resistance.

Definition 02.4 (Open Circuit).

Any circuit element with $R \rightarrow \infty$. In practice, this is a literal gap in the circuit, since air is a perfect insulator.

Conductance

Definition 02.5 (Conductance).

The ability of an element to conduct electric current; it is measured in mhos ($\mho$)/siemens (S).

$$ i = Gv$$

Power Dissipated by a Resistor

$$p = i^2 R = \frac{v^2}{R}$$ $$p = v^2 G = \frac{i^2}{G}$$
Example 02.6.

(Practice Problem 2.1 [Alexander & Sadiku, Fundamentals of Electric Circuits, 7th ed., p. 60])

1In [1]: eq = Eq(110**2 / 15, x * 110)
2
3In [2]: solve(eq, x)
4Out[2]: [7.33333333333334]
Example 02.7.

(Practice Problem 2.2 [Alexander & Sadiku, Fundamentals of Electric Circuits, 7th ed., p. 61])

1In [1]: v = 3e-3 * 10e3
2
3In [2]: G = 1/10e3
4
5In [3]: p = 3e-3**2 * 10e3
6
7In [4]: v, G, p
8Out[4]: (30.0, 0.0001, 0.09)
Example 02.8.

(Practice Problem 2.3 [Alexander & Sadiku, Fundamentals of Electric Circuits, 7th ed., p. 61])

 1In [2]: p = 30*cos(t)**2
 2
 3In [3]: v = 15*cos(t)
 4
 5In [4]: i = p / v
 6
 7In [5]: R = v**2 / p
 8
 9In [6]: i, R
10Out[6]: (2cos(t), 15/2)

Nodes, Branches, and Loops

Definition 02.9 (Branch).

Any two-terminal element in a circuit, such as a power source or resistor. The number of branches equals the number of circuit elements.

Definition 02.10 (Node).

The point of connection between two or more branches.

  • Typically indicated by a dot in a circuit
  • If a short circuit connects two nodes, the two nodes may be treated as a single node
Definition 02.11 (Loop).

Any closed path in a circuit.

  • A “closed path” starts at a node, passes through a set of nodes, and returns to the starting node without passing through any node more than once.
  • Is independent if it contains a branch that is not part of any other independent loop
    • Independent loops result in independent sets of equations
$$b = l + n - 1$$
Example 02.12.

(Practice Problem 2.4 [Alexander & Sadiku, Fundamentals of Electric Circuits, 7th ed., p. 63])

  • 5 elements, so 5 branches
  • 3 nodes
  • 4 $\Omega$ is in parallel with 10V
  • 1 $\Omega$ is in parallel with 2 $\Omega$

Kirchoff’s Laws

Kirchoff’s Current Law

Definition 02.13 (Kirchoff's Current Law).

The algebraic sum of currents entering/exiting a node is zero.

$$ \sum_{n=1}^{N} i_{n} = 0 $$

where $N$ is the number of branches connected to the node and $i_{n}$ is the $n$th current entering/exiting the node.

Kirchoff’s Voltage Law

Definition 02.14 (Kirchoff's Voltage Law).

The algebraic sum of all voltages around a loop is zero.

$$ \sum_{m = 1}^{M} v_{m} = 0 $$

where $M$ is the number of branches in the loop and $v_{m}$ is the $m$th voltage.

Example 02.15.

(Practice Problem 2.5 [Alexander & Sadiku, Fundamentals of Electric Circuits, 7th ed., p. 67])

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Example 02.16.

(Example 2.6 [Alexander & Sadiku, Fundamentals of Electric Circuits, 7th ed., p. 67])

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Example 02.17.

(Practice Problem 2.6 [Alexander & Sadiku, Fundamentals of Electric Circuits, 7th ed., p. 67])

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Example 02.18.

(Example 2.7 [Alexander & Sadiku, Fundamentals of Electric Circuits, 7th ed., p. 68])

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Example 02.19.

(Practice Problem 2.7 [Alexander & Sadiku, Fundamentals of Electric Circuits, 7th ed., p. 68])

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Example 02.20.

(Practice Problem 2.8 [Alexander & Sadiku, Fundamentals of Electric Circuits, 7th ed., p. 69])

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Series Resistance

Definition 02.21 (Equivalent Resistance of Series Resistors).

The equivalent resistance $R_{\text{eq}}$ of any number of resistors connected in series is the sum of the individual resistances.

$$R_{\text{eq}} = \sum_{n=1}^{N} R_{n}$$

Voltage Division

$$v_{n} = \frac{V_{s}R_{n}}{R_{\text{eq}}}$$

Parallel Resistances

Definition 02.22 (Equivalent Resistance of Parallel Resistors).

The equivalent resistance of two parallel resistors is equal to the product of their resistances divided by their sum.

$$R_{\text{eq}} = \frac{R_{1}R_{2}}{R_{1}+R_{2}}$$

For $n$ resistors in parallel, the equivalent resistance is

$$R_{\text{eq}} = \left(\sum_{n=1}^{N} \frac{1}{R_{n}}\right)^{-1}.$$
$$R_{\text{eq}} = \frac{R}{N}$$

Equivalent Conductance

$$G_{\text{eq}} = \sum_{n=1}^{N}G_{n}$$

where $G_{\text{eq}}$ = $\frac{1}{R_{\text{eq}}}$

$$G_{\text{eq}} = \left(\sum_{n=1}^{N}\frac{1}{G_{n}}\right)^{-1}$$

Current Division

$$i_{n} = i_{s}\left(\frac{R_{\text{eq}}}{R_{n}}\right),$$

or using the conductance definition:

$$i_{n} = \frac{i_{s}G_{n}}{G_{\text{eq}}}$$
Example 02.23.

(Practice Problem 2.12 [Alexander & Sadiku, Fundamentals of Electric Circuits, 7th ed., p. 76])

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Example 02.24.

(Practice Problem 2.13 [Alexander & Sadiku, Fundamentals of Electric Circuits, 7th ed., p. 77])

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Wye-Delta Transformations

Delta-Wye Conversion

$$\begin{align} R_{1} &= \frac{R_{b}R_{c}}{R_{a}+R_{b}+R_{c}} \\ R_{2} &= \frac{R_{c}R_{a}}{R_{a}+R_{b}+R_{c}} \\ R_{3} &= \frac{R_{a}R_{b}}{R_{a}+R_{b}+R_{c}} \end{align} $$

delta wye conversion example

Wye-Delta Conversion

$$\begin{align} R_{a} &= \frac{R_{1}R_{2}+R_{2}R_{3}+R_{3}R_{1}}{R_{1}} \\ R_{b} &= \frac{R_{1}R_{2}+R_{2}R_{3}+R_{3}R_{1}}{R_{2}} \\ R_{c} &= \frac{R_{1}R_{2}+R_{2}R_{3}+R_{3}R_{1}}{R_{3}} \end{align}$$

Balanced Condition

$$R_{Y} = \frac{R_{\Delta}}{3} \ \text{or} \ R_{\Delta}= 3R_{Y}$$
Example 02.25.

(Practice Problem 2.14 [Alexander & Sadiku, Fundamentals of Electric Circuits, 7th ed., p. 80])

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Example 02.26.

(Practice Problem 2.15 [Alexander & Sadiku, Fundamentals of Electric Circuits, 7th ed., p. 83])

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Sources

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