> anishgoyal


NotesEENG 3345: AC Circuit Analysis Lecture 5

AC Steady State Power, Mutual Inductance, Ideal Transformer

calendar_today   article 610 words   access_time 4 min   replay Modified

Table of Contents

RMS and Average Quantities

$$V_{\text{rms}} = \sqrt{\frac{1}{2\pi}\int_{0}^{2\pi} v^2(t) \, \mathrm{d}t} = \frac{V_{m}}{\sqrt{2}}$$$$I_{\text{rms}} = \frac{I_{m}}{\sqrt{2}}$$$$\begin{align} P_{\text{avg}} &= \frac{1}{T}\int_{0}^{T} p(t) \, \mathrm{d}t \\ &= \frac{V_{m}I_{m}}{2}\cos(\theta_{v} - \theta_{i}) \\ &= \frac{V_{m}I_{m}}{2}\cos(\phi) \end{align}$$

Types of Electric Power

$$\begin{align} P &= V I \cos(\phi_{V_{C}}-\phi_{I_{C}}) \\ &= VI\cos(\phi) \\ &= \Re(VI^*) \end{align}$$ $$\begin{align} Q &= V I \sin(\phi_{V_{C}}-\phi_{I_{C}}) \\ &= VI\sin(\phi) \\ &= \mathrm{Im}(V I^*) \end{align}$$ $$\begin{align} |S| &= |V||I| \\ &= |V I^*| \end{align}$$

power triangle

Complex Power

$$\begin{align} S &= P + jQ \\ &= V I^* \end{align}$$$$ |S| = \sqrt{P^2 + Q^2}$$

Power Factor

$$PF = \frac{P}{|S|}$$

Mutual Inductance

$$ M = \frac{N_2 \Phi_{21}}{I_1} = \frac{N_1 \Phi_{12}}{I_2} $$

Where:

$$ \varepsilon_1 = M \frac{dI_2}{dt} $$ $$ \varepsilon_2 = M \frac{dI_1}{dt} $$ $$ v_1 = L_1 \frac{di_1}{dt} \pm M \frac{di_2}{dt} $$ $$ v_2 = L_2 \frac{di_2}{dt} \pm M \frac{di_1}{dt} $$

Ideal Transformer

$$ \frac{N_1}{N_2} = a $$

Where $a$ is the turns ratio (primary to secondary).

$$ \frac{V_1}{V_2} = \frac{N_1}{N_2} $$ $$ \frac{I_1}{I_2} = \frac{N_2}{N_1} $$ $$ V_1 I_1 = V_2 I_2 $$
Example 05.1.

(Example 13.1 [Alexander & Sadiku, Fundamentals of Electric Circuits, 7th ed., p. 585])

05 AC Steady State Analysis, Mutual Inductance, Ideal Transformer 2025-07-07 08.01.13
Example 05.2.

(From Quiz 3 - Ch11)

05 AC Steady State Analysis, Mutual Inductance, Ideal Transformer 2025-07-07 08.32.49

References

Sources

Graph