Notes โบ MATH 5441: Financial Mathematics Lecture 8
Effective Rate of Discount
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Effective Rate of Discount
- Recall the effective rate of interest is equal to the amount of interest if it was just one installment at the end of the period
- The effective rate of discount is when the interest is paid at the beginning of the period
- Useful for loans and treasury bills
- “A loan of $1200 is made for one year at an effective rate of discount of 5%”
- The borrower pays $1200 \times 0.05 = 60$ (known as the discount amount) at the beginning to be able to use the money
- The borrower pays back the $1200 loan after the year is over
- If $k$ is borrowed at a discount rate of $d$, the discount amount is $kd$ to receive the use of $k$
- This means the borrower will only have $(k-kd) = k(1-d)$ to use from the loan amount after paying the interest upfront
- Effective rate of discount is therefore:
- $A(n)$ is the amount at the end of the $n$th period
- $D$ is the discount amount within the interval, which is just equal to $A(n)-A(n-1)$
Interest Vs Discount Model
- Interest model
- Payment for loan is made at the end of the interest period
- The borrower can make full use of the loan amount
- The effective rate is calculated based on the initial balance
- Discount model
- Payment for loan is upfront
- Borrower can make use of $k(1-d)$ of the loan
- Effective rate calculated from final balance
Relationship Between Effective Rates
$$i = \frac{d}{1-d}$$and
$$d = \frac{i}{1+i}$$- We can use this relationship to derive the following:
and
$$(1+i)(1-d) = 1$$and
$$i-d=id$$Compound Discount Function
$$A(t)(1-d)^{t} = A_{0}$$- Theorem: $d_{n} = d$ for all $n \ge 1$
Simple Discount Function
$$A(t)(1-dt) = A_{0}$$- Theorem: $d_n$ is increasing until $t = \frac{1}{d}$
Growth of Simple and Compound Discount Functions
- $(1-d)^t < 1 - dt, t \in (0, 1)$
- $(1-d)^t = 1-dt, t \in \{0, 1\}$
- $(1-d)^t > 1-dt, t > 1$